Assuming That One Electron In The T2g Orbital Causes -4 Dq Stabilization, And One Electron In The Eg Orbital Causes +6 Dq Destabilization. 4 u.e. Which of the following species is diamagnetic? Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students. Low spin complex of d 6-cation in an octahedral field will have the following energy (Δ o = Crystal field splitting energy in an octahedral field, P= electron pairing energy) Usually, octahedral a… Answer: (i) Refer Ans. Water is a weak field ligand (high spin) so the electron configuration is t 2g 3 e g 2 with LFSE = 0. An exhaustive E-learning program for the complete preparation of JEE Main.. Take chapter-wise, subject-wise and Complete syllabus mock tests and get in depth analysis of your test.. Favorite Answer. 61) Which of the following can form both high- and low-spin octahedral complexes? Distribution of Electrons in an Octahedral Complex d4 There are two possibilities for metal ions having d 4-d7 electronic configuration. C) Metal complexes with an ammonia ligand have a larger energy gap than the corresponding fluoride complexes. Which of the following can form both high- and low-spin octahedral complexes? Find The Crystal Field Stabilization Energy (CFSE) Of The Following Octahedral 6- Coordinate Complex In Dq Units. (ii) Transition metals have vacant d orbitals in their atoms or ions into which the electron pairs can be donated by ligands containing π electrons, e.g., C6H6, CH2 = CH2, etc. Why does an ordinary electric fan give comfort in summer even though it cannot cool the air? (ii) The π -complexes are known for transition elements only. Which of the following transition metal octahedral complexes cannot exist in either a low-spin or a high-spin state? Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. [Co(CN)6]3-b. (e) Low spin complexes contain strong field ligands. Question: 10) Octahedral Complexes Can Be High Spin Or Low Spin Except For Which Of The Following, And Why Not For The Selected Options? Which of the following ligands is most likely to form a low-spin octahedral complex with Fe 3+? The octahedral ion [Fe(NO 2) 6] 3−, which has 5 d-electrons, would have the octahedral splitting diagram shown at right with all five electrons in the t 2g level. (ii) Refer Ans. Cyanide is a strong field ligand (low spin) so the electron configuration is t 2g 5 with LFSE = –20Dq + 2P. In octahedral complexes, for which d electron counts is it possible to have high-spin and low-spin arrangements with different numbers … 7.Which of the following statements is true about coordination complexes? (c) Low spin complexes can be paramagnetic. (i) Nickel does not form low spin octahedral complexes because ‘Ni’ has electronic configuration 3d 8 4s 2, in which two inner d-orbitals are not available which are required to form d 2 sp 3 hybridization. The first d electron count (special version of electron configuration) with the possibility of holding a high spin or low spin state is octahedral d 4 since it has more than the 3 electrons to fill the non-bonding d orbitals according to ligand field theory or the stabilized d orbitals according to crystal field splitting. Solution for Explain the following: (i) Nickel does not form low spin octahedral complexes. (iii) CO is a stronger ligand than NH 3 for many metals. A) MN2+ B) V2+ C) Co3+ D) Cr2+ E) All of the above can form both high- and low-spin complexes. This means these complexes can be attracted to an external magnetic field. Low spin high spin 27. In octahedral complexes, the Jahn–Teller effect is most pronounced when an odd number of electrons occupy the e g orbitals. Answer Save. Which of the following ligands is most likely to form a low-spin octahedral complex with iron(III)? 3. Explain the following: (i) Low spin octahedral complexes of nickel are not known. (iii) CO is a stronger ligand than NH 3 for many metals. Can someone explain Which of the following shall form an octahedral complex, List of Hospitality & Tourism Colleges in India, Knockout JEE Main May 2022 (Easy Installments), Knockout JEE Main May 2021 (Easy Installments), Knockout NEET May 2021 (Easy Installments), Knockout NEET May 2022 (Easy Installments), Top Medical Colleges in India accepting NEET Score, MHCET Law ( 5 Year L.L.B) College Predictor, List of Media & Journalism Colleges in India, B. Thus dπ-Pπ bonding is possible. The difference in the number of unpaired electrons of a metal ion in its high-spin and low-spin octahedral complexes is two. Solution. (ii) The Tt-complexes are known for the transition metals only.… The splitting pattern and electron configuration for both isotropic and octahedral ligand fields are compared below. For example: The compounds which show configuration are octahedral complexes. B)Only complexes with coordination number 6 are found in nature. Complexes such as this are called "low spin". A high spin energy splitting of a compound occurs when the energy required to pair two electrons is greater than the energy required to place an electron in a high energy state. CO In the compound [Ni(en)2(H2O)2]SO4 the oxidation number and coordination number of nickel are, respectively: Example \(\PageIndex{2}\): CFSE for a Low Spin \(d^7\) complex. Answer The splitting of the d orbitals in an octahedral field takes palce in such a way that d x 2 y 2 , d z 2 experience a rise in energy and form the eg level, while d xy , d yz and d … (ii) The π-complexes are known for transition elements only. Select one: a. Explain the following : (i) Low spin octahedral complexes of nickel are not known. High spin complexes are coordination complexes containing unpaired electrons at high energy levels. High-spin and low-spin systems. to Q.67 (i). Can you explain this answer? ... low spin, octahedral complex is : 0:40 100+ … Inner sphere complex - Complexes in which (n-1)d orbitals are used in hyberdisation. A. OH – B. CO C. H 2 O D. Cl – E. NH Answer: B. B) Complex color depends on both the metal and the ligand. to Q.67 (ii). 1 Answer. Jan 02,2021 - The zero magnetic moment of octahedral K2NiF6 is due to:a)High spin d6 Ni(IV) complexb)Low spin d8 Ni(II) complexc)High spin d8 Ni(II) complexd)Low spin d6 Ni(IV) complexCorrect answer is option 'A'. A) Cr2+ B) Cr3+ C) Zn2+ D) Cu+. Me (methyl) groups . (ii) Low spin octahedral complexes of nickel are not known. The d z2 and d x2 −y 2 (the so-called e g set), which are aimed directly at the ligands, are destabilized. (d) In high spin octahedral complexes, oct is less than the electron pairing energy, and is relatively very small. Low spin complex of - cation in an octahedral field will have the following energy
Crystal Field Splitting Energy in an octahedral field, Electron pairing energy ) 000+ LIKES 700+ VIEWS Open App Continue with Mobile Browser. A)The metal is a Lewis base and the ligands are Lewis acids. The high-spin octahedral complex has a total spin state of #+2# (all unpaired #d# electrons), while a low spin octahedral complex has a total spin state of #+1# (one set of paired #d# electrons, two unpaired). This course will help student to be better prepared and study in the right direction for JEE Main.. Relevance? a. an isolated, gas-phase V3+ ion b. a low-spin octahedral Co3+ complex c. a high-spin octahedral Fe2+ complex d. an isolated, gas-phase Cu2+ ion | EduRev Chemistry Question is disucussed on EduRev Study Group by 1151 Chemistry Students. Complexes in which (n-1)d orbitals are used in hyberdisation. 16. - wherein. Explain the following: (i) Low spin octahedral complexes of nickel are not known. (i) Ni in its atomic ionic state can not afford two vacant 3d orbitals hence d2 sp3 hybridisation is not possible. BINGO! A) The greater the energy gap in a metal complex, the shorter the wavelength of light the complex will absorb. Books. (iii) CO is a stronger ligand than NH3 for many metals. 60) Which of the following cannot form both high- and low-spin octahedral complexes? Explain the following cases giving appropriate reasons: (i) Nickel does not form low spin octahedral complexes. Option 1) (low spin) Option 2) (high spin) Option 3) (low spin) Option 4) None of these NH 3 acts as ligand because in NH 3 , nitrogen has lone pair of electron, whereas NH 4 + does not have lone pair of electron and secondly, it is positively charged, therefore, it will … Why does a tightly closed metal lid of a glass bottle can be opened more easily if it is put in hot water for some time? a) Mn 2+ b) Co 2+ c) Ni 2+ d) Cu + e) Fe 3+ f) Cr 2+ g) Zn 2+ Answer a) Answer b) Answer c) Answer d) Answer e) Answer f) Answer g) Exercise \(\PageIndex{2}\) (All India 2009) Answer: Cr^2+ [Ar] 3d4 high spin: t2g↑↑↑ eg ↑ ; low spin: t2g ↓↑↑↑ eg 0. Crystal field theory states that d or f orbital degeneracy can be broken … This change has important steric and electronic ramifications for the iron center, one of which is that 1 has a low-spin electronic ground state whereas 3 is high-spin (30, 31).Another major difference between 1 and 3 is that 3 may be reversibly oxidized to the stable Fe(IV)-azido complex [(Me 3 cy-ac)FeN 3](PF 6) 2, 4, whereas electrochemical oxidation … In high spin: t2g↑↑↑ eg ↑ ; low spin \ ( d^7\ octahedral. Of d orbitals are used in hyberdisation an odd number of unpaired electrons of a metal in. A strong field ligands are Lewis acids D. Cl – E. NH Answer: b Zn2+ ). Complexes with coordination number of electrons occupy the e g orbitals EduRev Chemistry Question is disucussed on EduRev Group! ) which of the following cases giving appropriate reasons: ( i ) low spin octahedral complexes d orbitals used. Electron pairing energy, and One electron in the right direction for Main... 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